If dimensions of critical velocity
of a liquid flowing through a tube are expressed as
where
and
are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x, y and
are given by
Text Solution
Verified by ExpertsThe correct answer is:
A
Critical velocity of liquid flowing through a tube are expressed as

Coefficient of viscosity of liquid,

Density of liquid,
Radius of a tube
Critical velocity of liquid, 

Comparing exponents of
and L, we get

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